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  • Refer to the arrangement of charges in Fig. 1.6 and a Gaussian surface of radius R with Q at the centre. Then

Refer to the arrangement of charges in Fig. 1.6 and a Gaussian surface of radius R with Q at the centre. Then

A. total flux through the surface of the sphere is \frac{-Q}{\varepsilon _0}

B. field on the surface of the sphere is \frac{-Q}{4\pi \varepsilon _0R^{2}}.
C. flux through the surface of sphere due to 5Q is zero.
D. field on the surface of sphere due to –2Q is same everywhere.

Answers (1)

The correct answers are the options (a,c)

Explanation: 5Q charge lies outside the Gaussian surface, hence making no contribution to the electric flux. So, a and c are correct options.

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infoexpert21

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