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  • If there were only one type of charge in the universe then A oint_{s}E.ds neq 0 on any surface

If there were only one type of charge in the universe, then
A.   \oint_{s}E.ds\neq 0     on any surface
B.  \oint_{s}E.ds= 0if the charge is outside the surface.
C. \oint_{s}E.dscould not be defined.

D.\oint_{s}E.ds= \frac{q}{\varepsilon _0} if charge of magnitude q were inside the surface.

Answers (1)

The correct answers are the options (b,d)

Explanation:\phi _{s}E . dS= \frac{q}{\varepsilon _0}  from Gauss' law. Therefore, if \phi _{s}E . dS= 0 then q=0, therefore the net enclosed charge should be 0. And if the charge is outside the surface then also q=0. Therefore, (b,d) are correct.

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infoexpert21

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