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  • Find the domain and Range of the function f (x) = 1/√(x-5)

Find the domain and Range of the function f (x) = 1/\sqrt{(x-5)}.

Answers (1)

Given data: f (x) = 1/\sqrt{(x-5)}

When, x-5>0, i.e., x>5, f(x) is real

  Thus, domain = (5, \infty)

Now, in order to find the range, we will put

y = f(x) = 1/\sqrt{x-5}

Thus,\sqrt{x-5 }= 1/y

x-5 = 1/y^2

x = 1/y^2 + 5

Therefore, for x \in (5, \infty), y \in R.

Therefore, range off = R^+
 

Posted by

infoexpert21

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