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The domain for which the functions defined byf (x) = 3x^2 - 1 and g (x) = 3 + xare equal is

A.\left \{ -1,\frac{4}{3} \right \}

B.\left [ -1,\frac{4}{3} \right ]

C.\left ( -1,\frac{4}{3} \right )

D.\left [ -1,\frac{4}{3} \right )

Answers (1)

Given data: f (x) = 3x^2 - 1 and g (x) = 3 + x

Now, f(x) = g(x)

Thus,

3x^2 - 1 = 3 + x

x(3x-4) + 1(3x-4) = 0

Thus, x+1 = 0 or 3x-4 = 0

Thus, x = -1 or x = 4/3

Thus, its domain is \{ -1, 4/3\}

Therefore, (a) is the correct option.

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infoexpert21

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