Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • NCERT
  • Let f(x) = √(1+x^2 ), then A. f (xy) = f (x) . f (y) B. f (xy) \geq f (x) . f (y) C. f (xy) \leq f (x) . f (y) D. None of these

Let f(x)=\sqrt{(1+x^2 )}, then
A. f (xy) = f (x) . f (y)
B. f (xy) \geq f (x) . f (y)
C. f (xy) \leq f (x) . f (y)
D. None of these

Answers (1)

Given data: f(x)=\sqrt{(1+x^2 )},

f(xy) = \sqrt{(1+x^2 y^2 )}

f(x).f(y) = \sqrt{(1+x^2 )}. \sqrt{(1+x^2 y^2 )}

=\sqrt{1+x^2+y^2+ x^2 y^2 }

Thus, \sqrt{1+x^2 y^2 } \leq \sqrt{1+x^2+y^2+ x^2 y^2 }

i.e.,f(xy)\leq f(x).f(y)

Thus, (c) is the correct answer.

Posted by

infoexpert21

View full answer

Similar Questions

Latest Question