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  • Domain of squareroot8squareminusxsquarebracketagreaterthan0 is

Domain of \sqrt{a^2-x^2 } (a>0) is

A. (- a, a)
B. [- a, a]
C. [0, a]
D. (- a, 0]

Answers (1)

Let us take,

f(x) = a^2-x^2

& f(x) is defined at a^2-x^2\geq 0

x^2-a^2 \leq 0

x^2\leq a^2

Thus, -a\leq x\leq a

Thus, domain of f(x) will be [-a,a]

Therefore, (b) is the correct answer.

 

Posted by

infoexpert21

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