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  • Following table gives the distribution of students of sections A and B of a class according to the marks obtained by them.Represent the marks of the students of both the sections on the same graph by two frequency polygons. What do you observe?

Following table gives the distribution of students of sections A and B of a class according to the marks obtained by them.

Section A Section B
Marks Frequency Marks Frequency
0-15 5 0-15 3
15-30 12 15-30 16
30-45 28 30-45 25
45-60 30 45-60 27
60-75 35 60-75 40
75-90 13 75-90 10

Represent the marks of the students of both the sections on the same graph by two frequency polygons. What do you observe?

Answers (1)

\text{Formula of to find the class marks }=\frac{\text {upper class limit}+\text {lower class limit}}{2}

Marks Class marks Frequency A Frequency B
0-15 0+15=\frac{15}{2}=7.5 5 3
15-30 \frac{15+30}{2}=\frac{45}{2}=22.5 12 16
30-45 \frac{30+45}{2}=\frac{75}{2}=37.5 28 25
45-60 52.5 30 27
60-75 67.5 35 40
75-90 82.5 13 10

A frequency polygon is a graph constructed by using lines to join the midpoints of each interval.

Points where frequency is zero:

Difference = 22.5 - 7.5 = 15

First Point =7.5-15 = -7.5

Last point =82.5+7.5= 90

So we can construct the frequency polygon of A (orange) and B (blue) as follows:

Posted by

infoexpert23

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