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  • Let m be the mid-point and l be the upper class limit of a class in a continuous frequency distribution. The lower class limit of the class is : (A) 2m+l (B) 2m-l (C) m-l (D) m-2l

Let m be the mid-point and l be the upper-class limit of a class in a continuous frequency distribution. The lower class limit of the class is :

(A)\; 2m+l

(B)\; 2m-l 

(C)\; m-l 

(D)\; m-2l

Answers (1)

Answer : B

Given, l is the upper limit of class

Let n be the lower class limit

Also given, m is the mid-point of this class.

Mid value of a class is calculated as follows:

\frac{\text {upper limit+lower limit}}{2}

Then, mid-point

m=\frac{n+l}{2}

2m=n+l

Therefore, n=2m-l

Therefore option (B) is correct.

Posted by

infoexpert23

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