If AB = QR, BC = PR and CA = PQ, then
[B]
Solution. AB = QR, BC =PR, CA = PQ (Given)
Triangles follow the SSS criterion for congruence
In option , from this we conclude that side AB = PQ
But it is given AB = QR and AB = PQ may or may not be possible
In option, by same relation, we say that
side BA = RP may or may not be possible because it is given BA = QP
In option
side PQ = BC may or may not be possible
In option ,
CB = PR, BA = RQ, AC = QP (all are given.)
Hence option (B) is correct.