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 If an electric iron of 1200 W is used for 30 minutes every day, find electric energy consumed in the month of April.

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Answer: 64800000J

Solution.
The electrical energy consumed is calculated in units.
We know that one unit is equal to the energy of 1 kilowatt-hour.
Power of heater = 1200 watt =1.2 kilowatt
Per day usage = 30 minutes = 0.5 hour
Energy consumed per day = (1.2 kilowatt) (0.5 hour) = 0.6 units.
In April, total number of days = 30
Therefore, total consumption will be: Energy = (30) (0.6) = 18 units
It can be converted in joules:
1unit=1000\times 3600J
\Rightarrow 18unit=(18\times 1000\times 3600)J=64800000J
 

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