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  • In \trianglePQR, if \angleR > \angleQ, then (A) QR > PR (B) PQ > PR (C) PQ < PR (D) QR < PR

In \trianglePQR, if \angleR > \angleQ, then

(A) QR > PR

(B) PQ > PR

(C) PQ < PR

(D) QR < PR

Answers (1)

[B]

Solution.        

We know that side opposite to the greater angle is longer.

Here \angleR > \angleQ

Therefore, PQ > PR

Hence option (B) is correct.

Posted by

infoexpert24

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