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(n-1) equal point masses each of mass m are placed at the vertices of a regular n-polygon. The vacant vertex has a position vector a with respect to center of the polygon. Find the position vector of center of mass.

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The centre of mass of a regular polygon with n sides lies on its geometric centre. If mass m is placed at all the n vertices, then the C.O.M is again at the geometric centre. Let   \overrightarrow{r} be the position vector of the COM and  \overrightarrow{a} of the vacant vertex. Then

r_{cm}=\frac{(n-1)mr+ma}{(n-1)m+m}=0 (when mass is placed at nth vertex also)

(n-1)mr+ma=0

r=-\frac{ma}{(n-1)m}

\overrightarrow{r}=-\frac{\overrightarrow{a}}{(n-1)}

The negative sign depicts that the C.O.M lies on the opposite side of the nth vertex.

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