Get Answers to all your Questions

header-bg qa

P and Q are points on opposite sides of AD and BC of a parallelogram ABCD such that PQ passes through the point of intersection O of its diagonals AC and BD. Show that PQ is bisected at O.

Answers (1)

Given: ABCD is a parallelogram whose diagonals bisect each other at O.
To Prove: PQ is bisected at O.


Proof: In \triangle ODP and \triangle OBQ
\angle BOQ=\angle POD {Vertically opposite angles}
\angle OBQ=\angle ODP {interior angles}
OB = OD {given}
\triangle ODP\cong \triangle OBQ {by ASA congruence}
OP = OQ {by CPCT rule}
So, PQ is bisected at O.

Posted by

infoexpert26

View full answer