Photon is quantum of radiation with energy E = hv where v is frequency and h is Planck’s constant. The dimensions of h are the same as that of:

a) linear impulse

b) angular impulse

c) linear momentum

d) angular momentum

Answers (1)

The answer is the option (b) Angular Impulse and (d) Angular momentum

Explanation: It is given that E = hv

Hence, h (Planck’s constant) =\frac{E}{v}

                  =\frac{[ML^{2}T^{-2}]}{[T^{-1}]}

                   =[ML^{2}T^{-1}]

Now, Linear Impulse = F.t

                      =\frac{dp}{dt}.dt=dp

                      =mv=[MLT^{-1}]

& Angular Impulse = = \tau.dt= \frac{dL}{dt}.dt

                                  = dL= mvr

                                  = [M][LT^{-1}][L]

                                  = [ML^{2}T^{-1}]

Now, Linear momentum = mv

                                     = [MLT^{-1}]

& Angular momentum (L) = mvr

                                       = [ML^{2}T^{-1}]

Thus, the dimensional formulae of Planck’s constant, Angular Impulse and Angular Momentum are the same.

 

 

 

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