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Susan invested certain amount of money in two schemes A and B, which offer interest at the rate of 8% per annum and 9% per annum, respectively. She received Rs 1860 as annual interest. However, had she interchanged the amount of investments in the two schemes, she would have received Rs 20 more as annual interest. How much money did she invest in each scheme

Answers (1)

Solution:
Let money invested in A and B are x, y respectively.
So, according to question.
0.08x + 0.09y = 1860                 … (1)

x\times \frac{9}{100}+y\times \frac{8}{100}= 1880
0.09x + 0.08y = 1880              … (2)
Multiply equation (1) by 9 and (2) by 8
0.72x + 0.81y = 16740
0.72x + 0.64y = 15040
–             –              –
0.17y = 1700

y = \frac{1700}{0\cdot 7}= 10000
Put y = 10000 in eq. (1)
0.08x + 900 = 1860
0.08x = 960
x = \frac{960}{8}\times 100 = 12000
x = 12000
He invested Rs. 12000 in A and Rs. 10000 in B.

 

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