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The amplifiers X, Y and Z are connected in series. If the voltage gains of X, Y and Z are 10, 20 and 30, respectively and the input signal is 1 mV peak value, then what is the output signal voltage (peak value)

(i) if dc supply voltage is 10V?
(ii) if dc supply voltage is 5V?

Answers (1)

The ratio of output signal voltage to the input signal voltage is known as the total voltage amplification.

According to the problem, voltage gain in X, Vx =10

Voltage gain un Y; V= 20

Voltage gain un Z; V= 30

\triangle V_{i}=l m V=10^{-3}V

And total voltage amplification =

V_{x}\times V_{y}\times V_{z}

\triangle V_{0}=V_{x}\times V_{y}\times V_{z}\times V_{i}\\ =10\times 20\times 30\times 10^{-3} V=6V

(i) If the DC supply voltage is 10 V, then output is 6 V since the theoretical gain is equal to the practical gain, i.e., output can never be greater than 6 V.

(ii) If the DC supply voltage is 5 V, i.e., Vcc = 5V,. Then the output peak will not exceed 5V. hence V0=5V.

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