# The water for a factory is stored in a hemispherical tank whose internal diameter is 14 m. The tank contains 50 kilolitres of water. Water is pumped into the tank to fill to its capacity. Calculate the volume of water pumped into the tank.

Answer : $668.66 \; m^{3}$

We know that Volume of hemispherical tank$=\frac{2}{3}\pi r^{3}$

Where, r = radius of hemispherical tank

Now, internal diameter of hemispherical tank is given as 14 m

So, internal radius of hemispherical tank$=\frac{14}{2}=7\; m$

Tank contains 50 kL of water

We have, $1000 \; L=1\; m^{3}$

So, $1\; kL=1\; m^{3}$

This means that tank contains $50\; m^{3}$ of water

$\Rightarrow$ Volume of hemispherical tank $=\frac{2}{3}\times\frac{22}{7}\times \left ( 7 \right )^{3}=\frac{2156}{3}=718.66\; m^{3}$

Now, as we are given that the already tank contains 50 kilolitres of water

Volume of water pumped into the tank = Total Volume of hemispherical tank $-50\; m^{3}$

Volume of water pumped into the tank $=\left ( 718.66-50 \right )m^{3}=668.66\; m^{3}$

Hence the answer is $668.66\; m^{3}$

## Similar Questions

### Preparation Products

##### Knockout NEET May 2021 (One Month)

An exhaustive E-learning program for the complete preparation of NEET..

₹ 14000/- ₹ 6999/-
##### Foundation 2021 Class 10th Maths

Master Maths with "Foundation course for class 10th" -AI Enabled Personalized Coaching -200+ Video lectures -Chapter-wise tests.

₹ 350/- ₹ 112/-
##### Knockout JEE Main April 2021 (One Month)

An exhaustive E-learning program for the complete preparation of JEE Main..

₹ 14000/- ₹ 6999/-
##### Knockout NEET May 2021

An exhaustive E-learning program for the complete preparation of NEET..

₹ 22999/- ₹ 14999/-