The width of each of five continuous classes in a frequency distribution is 5 and the lower class-limit of the lowest class is 10. The upper class-limit of the highest class is:
Answer: C
Here, lower class-limit of the lowest class is 10 and the width of the class is 5
So, starting from 10 the first class will be:
Now we have been given that this is the lowest class. So next 4 continuous classes will be:
As the total number of classes is 5, so 35 is the upper limit of the highest class.
Therefore option (C) is correct.