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  • Two molecules of a gas have speeds of 9 x 10^16 ms^-1 and 1 x I0^6 ms^-1 respectively. What is the root mean square speed of these molecules?

Two molecules of a gas have speeds of 9 \times 10^{16} ms^{-1} and 1 \times 10^{16} ms^{-1} respectively. What is the root mean square speed of these molecules? 

Answers (1)

V_{rms}=\sqrt{\frac{V1^{2}+V2^{2}...........Vn^{2}}{n}}  

We know that, V_{1}=9 \times 10^{16} ms^{-1} and V_{2}=1 \times 10^{16} ms^{-1}

Hence, V_{rms}=\sqrt{\frac{\left ( 9 \times 10^{6} \right )^{2}+\left ( 1\times 10^{6} \right )^{2}}{2}}

V_{rms}=10^{6}\times \sqrt{\frac{82}{2}}=6.4 \times 10^{6} m/s

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infoexpert24

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