Use the molecular orbital energy level diagram to show that N_{2} would be expected to have a triple bond, F_{2} a single bond and Ne_{2} no bond.

Answers (1)

The general sequence of the energy level of molecular orbitals for nitrogen is:

\sigma 1s<\sigma ^{*}1s<\sigma 2s<\sigma ^{*}2s<\pi 2p_{x}=\pi 2p_{y}<\sigma 2p_{z}

The molecular orbitals in the sequence of their energy levels for the given molecules have hereby been described below:

N_{2}\sigma 1s^{2}\; \sigma^{*} 1s^{2}\; \sigma 2s^{2}\sigma^{*} 2s^{2}\pi 2p{_{x}}^{2}=\pi 2p{_{y}}^{2}\sigma 2p{_{z}}^{2}

Now, we know that the,

Bond order for N_{2}=\frac{8-2}{2}=3

Now, as the bond order is 3, it means that N_{2} will have a triple bond.

The molecular orbital of Fluorine has been described below: -

F_{2}= \sigma 1s^{2}, \sigma ^{*} 1s^{2}, \sigma 2s^{2}, \sigma ^{*} 2s^{2}, \sigma \; 2px^{2}, \pi 2px^{2} = \pi 2py^{2}

The bond order of F_{2}=\frac{10-8}{2}=1

Thus, we can imply that when the bond order is 1, the number of bonds must also be 1.

Ne_{2}= \sigma 1s^{2}, \sigma ^{*} 1s^{2}, \sigma 2s^{2}, \sigma ^{*} 2s^{2}, \sigma \; 2px^{2}, \pi 2px^{2} = \pi 2py^{2},\pi ^{*}2p{_{x}}^{2}=\pi ^{*}2p{_{y}}^{2}

Now, we can calculate the bond order of Ne_{2}=\frac{10-10}{2}=0

Thus, Ne_{2} has no bond.

Most Viewed Questions

Preparation Products

Knockout NEET 2024

Personalized AI Tutor and Adaptive Time Table, Self Study Material, Unlimited Mock Tests and Personalized Analysis Reports, 24x7 Doubt Chat Support,.

₹ 40000/-
Buy Now
Knockout NEET 2025

Personalized AI Tutor and Adaptive Time Table, Self Study Material, Unlimited Mock Tests and Personalized Analysis Reports, 24x7 Doubt Chat Support,.

₹ 45000/-
Buy Now
NEET Foundation + Knockout NEET 2024

Personalized AI Tutor and Adaptive Time Table, Self Study Material, Unlimited Mock Tests and Personalized Analysis Reports, 24x7 Doubt Chat Support,.

₹ 54999/- ₹ 42499/-
Buy Now
NEET Foundation + Knockout NEET 2024 (Easy Installment)

Personalized AI Tutor and Adaptive Time Table, Self Study Material, Unlimited Mock Tests and Personalized Analysis Reports, 24x7 Doubt Chat Support,.

₹ 3999/-
Buy Now
NEET Foundation + Knockout NEET 2025 (Easy Installment)

Personalized AI Tutor and Adaptive Time Table, Self Study Material, Unlimited Mock Tests and Personalized Analysis Reports, 24x7 Doubt Chat Support,.

₹ 3999/-
Buy Now
Boost your Preparation for JEE Main with our Foundation Course
 
Exams
Articles
Questions