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explain solution rd sharma class 12 chapter 14 Mean Value Theoram exercise multiple choice question 4 maths

Answers (1)

Answer:

Option (c)

Hint:

Prove mean value theorem

Given: f^{'}(x_{1})=\frac{f(b)-f(a)}{b-a}

Solution:

Mean value theorem,

            f(x) is continuous in \left [ a,b \right ]

            f(x) is differentiable in \left ( a,b \right )

            f^{'}(x_{1})=\frac{f(b)-f(a)}{b-a}

            a< x_{1}< b

\therefore f^{'}(x_{1})=\frac{f(b)-f(a)}{b-a}

\Rightarrow a< x_{1}< b

Hence, option (c) is correct.

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