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Explain solution RD Sharma class 12 chapter Increasing and Decreasing Functions exercise 16.2 question 28 maths

Answers (1)

Answer:

f(x) is increasing for all x.

Given:

f(x)=10^{x}

To find:

We have to show that f(x) is increasing for all x.

Hint:

Condition to be function is increasing i.e, f ‘(x) > 0

Solution:

We have,

f(x)=10^{x}

On differentiating both sides w.r.t. x we get,

\begin{aligned} &f^{\prime}(x)=10^{x} \times \log 10,\left[\therefore \frac{d}{d x} a^{x}=a^{x} \log a\right] \\ &\text { Now, } x \in R \\ &\Rightarrow 10^{x}>0 \\ &\Rightarrow 10^{x} \log 10>0 \\ &\Rightarrow f^{\prime}(x)>0 \end{aligned}

Hence, f(x) is an increasing function for all x.

Posted by

Gurleen Kaur

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