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Need solution for RD Sharma maths class 12 chapter Increasing and Decreasing Functions exercise 16.2 question 27

Answers (1)

Answer:

f(x) is increasing in (-\infty,-1)

and f(x) is decreasing in (-1,\infty)

Given:

f(x)=(x+2)e^{-x}

To find:

We have to find the intervals in which f(x) is increasing and decreasing.

Hint:

First, we find critical point then find property of increasing and decreasing intervals.

Solution:

we have

f(x)=(x+2)e^{-x}

Differentiating w.r.t. x we get,

\begin{aligned} &f^{\prime}(x)=e^{-x}-e^{-x}(x+2) \\ &=e^{-x}(1-x-2) \\ &=-e^{-x}(x+1) \end{aligned}

For critical points.

\begin{aligned} &f^{\prime}(x)=0 \\ &\Rightarrow-e^{-x}(x+1)=0 \\ &\Rightarrow x=-1 \\ &\text { Clearly, } f^{\prime}(x)>0 \text { if } x<-1 \\ &\text { and } f^{\prime}(x)<0 \text { if } x<-1 \end{aligned}

Hence, f(x) is increasing in (-\infty,-1), decreasing in (-1,\infty)

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Gurleen Kaur

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