Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • School
  • Please Solve RD Sharma Class 12 Chapter 11 Higher Order Derivatives Exercise Multiple Choice Questions Maths Textbook Solution Question 2

Please Solve RD Sharma Class 12 Chapter 11 Higher Order Derivatives Exercise Multiple Choice Questions Maths Textbook Solution Question 2

Answers (1)

Answer:

                (d)

Hint:

We must know about the derivative of  t .

Given:

                x=a t^{2}, y=2 a t

 

Explanation:

                 x=a t^{2}

                 \Rightarrow \quad \frac{d x}{d t}=2 a t

                 y=2 a t

                 \Rightarrow \frac{d y}{d t}=2 a

                \begin{aligned} & \frac{d y}{d x}=\frac{\frac{d y}{d t}}{\frac{d x}{d t}}=\frac{2 a}{2 a t} \\ \end{aligned}

               \Rightarrow \frac{d y}{d x}=\frac{1}{t}

Differentiate on both sides,

                 \begin{aligned} &\frac{d^{2} y}{d x^{2}}=\frac{d}{d x}\left(\frac{d y}{d x}\right) \\ & \end{aligned}

                =\frac{d}{d t}\left(\frac{d y}{d x}\right) \times \frac{d t}{d x}

                \begin{aligned} &=\frac{d}{d t}\left(\frac{1}{t}\right) \times \frac{1}{2 a t} \\ \end{aligned}

                =\frac{-1}{t^{2}} \times \frac{1}{2 a t} \\

                =\frac{-1}{2 a t^{3}}

Posted by

infoexpert27

View full answer

Crack CUET with india's "Best Teachers"

  • HD Video Lectures
  • Unlimited Mock Tests
  • Faculty Support
cuet_ads

Similar Questions

Trending Articles/News

anam-khan

PM Modi's Pariksha Pe Charcha 2025 to be held next month, registrations open till January 14
anam-khan

CBSE Board Exams 2025: Online portal for availing exemptions by CWSN students opens
anam-khan

Board Exams: States agree to equivalence; no question paper ‘jumbling’ from next year, says PARAKH CEO

Latest Question