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  • Provide solution for RD Sharma maths class 12 chapter 31 Mean and Variance of a Random Variable exercise 31.1 question 4 sub question 3 maths textbook solution

Provide solution for RD Sharma maths class 12 chapter 31 Mean and Variance of a Random Variable exercise 31.1 question 4 sub question 3 maths textbook solution

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Answer: So, the required value of : P\left ( x< 2 \right )=\frac{2}{3}

Hint: P\left ( 1<x\leq 2 \right )=P\left ( 2 \right )

Given:

X 0 1 2
P\left ( X \right ) 3c^{3} 4c-10c^{2} 5c-1


Solution: P\left ( 1<x\leq 2 \right )=P\left ( 2 \right ) 

P\left ( 1<x\leq 2 \right )=5c-1

P\left ( 1<x\leq 2 \right )=5\left ( \frac{1}{3} \right )-1

\therefore P\left ( 1<x\leq 2 \right )=\frac{2}{3}

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