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Provide Solution For  R.D. Sharma Maths Class 12 Chapter 31 Mean and Variance of a random Exercise Very Short Answer type Question 4 Maths Textbook Solution.

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Answer:  k = 0.1

Hint: - You must know the rules for solving probability distribution problems.

Given: -

          \begin{array}{|c|c|c|c|c|} \hline X=x_{i} & 1 & 2 & 3 & 4 \\ \hline P\left(X=x_{i}\right) & 2 k & 4 k & 3 k & k \\ \hline \end{array}

Solution: - We know the sum of probabilities in a probability distribution is always 1.

\begin{aligned} &\sum_{i=1}^{n} p_{i}=1 \\\\ &\therefore P(x=1)+P(x=2)+P(x=3)+P(x=4)=1 \\\\ &2 k+4 k+3 k+k=1 \\\\ &10 k=1 \\\\ &k=\frac{1}{10} \\\\ &=0.1 \end{aligned}

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