Get Answers to all your Questions

header-bg qa

Provide solution for RD Sharma maths class 12 chapter 31 Mean and Variance of a Random Variable exercise 31.1 question 1 sub question 4 maths textbook solution

Answers (1)

Answer: The given distribution of probability is a probability distribution

Hint: \sum P\left ( x=n \right )=1

Given:

X 0 1 2 3
P\left ( X \right ) 0.3 0.2 0.4 0.1

 

Solution:

 P(x=0)+P(x=1)+P(x=2)+P(x=3)

=0.3+0.2+0.4+0.1

=1

So, the given distribution of probability is a probability distribution.

Posted by

Infoexpert

View full answer