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Name: Explain solution RD Sharma class 12 Chapter 29 Linear Programming exercise 29.4 question 11
Uploaded: Mon, 2021-09-06 22:49
Description: Explain solution RD Sharma class 12 Chapter 29 Linear Programming exercise 29.4 question 11

Explain solution RD Sharma class 12 Chapter 29 Linear Programming exercise 29.4 question 11

Answers (1)

Answer:

Maximum profit = Rs. 2025 could be obtained if 45 units of chairs and no units of table are produce.

Hint:

Use graph and simultaneous equation

Given:

Resources available 400square feet of teak wood and 450 man hours.

Solution:

Let required production of chairs and tables be z=x and y respectively.

Since, profits of each chair and table is Rs45 and Rs80 respectively

So, profit on x number of type A and y number of type B are 45x and 80y respectively.

Let z denotes total output daily so,

$z=45x+80y$

Since each chair and table require 5 sq. and 80sq.ft of wood respectively. So, x number of chair and y number of table require 5x and 80y sq. of wood respectively. But 400sq.ft of wood available

So,
.
$5x+80y\leq 400$

$x+4y\leq 80$ (first constraints)

Since, each chair ad table requires 10 and 25 man hours respectively, so, x number of chair and y number of tables are require 10x and 25y men hours respectively. But, only 450 hours are available.

So,

$10x+25y\leq 450$