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Please Solve R.D. Sharma class 12 Chapter 29 Linear Programming Exercise 29.3 Question 2 Maths Textbook Solution.

Answers (1)

Answer: 185

Hint: Draw a graph

Solution:Let x unit of food A and y unit of Food B.                                         

           \therefore  Minimum cost:5x+4y=z                       

           Sub to,

            200x+100y\geq 4000

       \begin{aligned} &\Rightarrow \quad 2 x+100 y \geq 40 \\ &\Rightarrow \quad x+2 y \geq 50 \\ &\Rightarrow \quad x+y \geq 35 \\ \end{aligned}

                 \begin{aligned} &x \geq 0, y \geq 0 \end{aligned}

Solving (i),(ii);x=5,y=30

Solving (ii),(iii);x=20,y=15

Points Value of z
A(0,40) 160
B(5,30) 135
C(20,15) 160
D(50,0) 250

       Minimum cost is 135.

                                                                    

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