Get Answers to all your Questions

header-bg qa

Please Solve RD Sharma Class 12 Chapter 29 Linear Programming Exercise 29.4 Question 42 Maths Textbook Solution.

Answers (1)

Answer: The society will get the maximum profit of Rs.495000 by allocating 30 hectares for crop X and 20 hectare for Crop y.

Hint:

Let x hectare of land be allocated to crop x and y hectare to crop y.

Given:

Profit per hectare on crop x=Rs.10500

Profit per hectare on crop y = Rs.9000

Solution:

By the given profit on x crop and y crop.

Total profit=Rs.(10500x+9000y)

The mathematical formulation of the problem is as follows.

Maximize Z = 10500x + 9000y

Subject to the constraints

x+y \leq 50 (Constraint related to land)                                                                                                   … (i)

20 x+10 y \leq 800 (Constraint related to use of herbicide) i.e 2 x+8 y \leq 80                              … (ii)

x \geq 0 \& y \geq 0 (Non –negative constraint)                                                                                                              … (iii)

Let us draw the graph of the system of inequalities (i) to (iii).

The feasible region ABC is shown (shaded)

 

Corner Points

Z=10500x+9000y

O(0,0)

0

A(40,0)

420000

B(30,20)

495000(Maximum)

C(0,50)

450000

 

The coordinate of the corner points O, A, B and C are (0,0), (45,0),(30,20) and (0,50) respectively.

Let us evaluate the objection function Z = 10500x + 9000y at these vertices to find on gives the maximum profit.

Hence, the society will get the maximum profit of Rs.495000 by allocating 90 hectares for crop x and 20 hectares for crop y.

Posted by

infoexpert27

View full answer

Crack CUET with india's "Best Teachers"

  • HD Video Lectures
  • Unlimited Mock Tests
  • Faculty Support
cuet_ads