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  • Need solution for RD Sharma maths class 12 chapter Linear Programming exercise 29.2 question 19

Need solution for RD Sharma maths class 12 chapter Linear Programming exercise 29.2 question 19

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Answer: the maximum value of Z is 3

Hint: Plot the points on the graph

Given: ? =x+y

Solution: We need to maximize ? =x+y . First, we will convert the given equations, awe obtain the following equations;

                -2 x+y=1, x=2, x+y=3, u=0, y=0

The line -2 x+y=1  meets the coordinates axis at A\left(-\frac{1}{2}, 0\right) \text { and } B(0,1). Join these points to obtain the line -2 x+y=1 . Clearly (0, 0), satisfies the equations -2 x+y \leq 1  . So the region xy-plane that

contains the origin represents the section set of the given equation.

U=2 , is the line passing through (2,0) and parallel to the y-axis. The region below the line u=2 will satisfy the given equation.

The line x+y=3 meets the coordinates axis at c(3, 0) . clearly, (0, 0) satisfies the equation x+y \leq 3 . So the region xy-plane that contains the origin represents the solution set of the given equation

Region represented by u \geq 0 \text { and } y \geq 0 . Since every point in the first quadiant satisfies the equation, so the first quadrant is the region represented by the inequalities

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