Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • School
  • Explain solution RD Sharma class 12 chapter Linear Programming exercise 29.2 question 28 maths

Explain solution RD Sharma class 12 chapter Linear Programming exercise 29.2 question 28 maths

Answers (1)

best_answer

Answer: the minimum value of Z is 150

Hint: plot the point on the graph

Given: minimize z=6 x+3 y

Solution: the given constraints are 4 x+y \geq 80, x+y \geq 115,3 x+2 y \geq 150, x, y \geq 0

Converting the given equations into equations we get 4 x+y=80, x+y=115,3 x+2 y=150, x, y=0

The lines are drawn on the graph and the shaded region A,B,C represents the feasible region of the given LPP

It can be observed that the feasible region is bounded thus the coordinates of the corner points of the feasible region A(2, 22)\; \; B(12, 30) and C(40, 15). The value of function Z at the corner points are given in the following table;

\begin{array}{|l|l|} \hline \text { Corner Point } & \text { Values of the objective } Z=6 x+2 y \\ \hline A(2,22), & z=6(2)+3(22)=228 \\ B(15,20) & z=6(15)+3(20)=150 \\ C(40,15) & z=6(40)+3(15)=285 \\ \hline \end{array}

From the table, Z is minimum at x=15 and  y=20  and the minimum value of Z is 150

Posted by

infoexpert26

View full answer

Crack CUET with india's "Best Teachers"

  • HD Video Lectures
  • Unlimited Mock Tests
  • Faculty Support
cuet_ads

Similar Questions

Trending Articles/News

anam-khan

CBSE Class 12 result verification 2024 application out at cbse.gov.in; last date, fees
anam-khan

CBSE results 2024 later for 102 students over fake certificates; board issues show cause notice
anam-khan

What after CBSE Class 12 results 2024? From CUET UG to JEE Advanced, all you need to know

Latest Question