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Provide solution for RD Sharma maths class 12 chapter Linear Programming exercise 29.2 question 10

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Answer:

The optimal value of z is 20.

Hint:

Plot the points on the graph.

Given:

z=2x+4y

Solution:

First, we will convert the given in equations into equations, we obtain the following equations

x+y=8,x+4y=12, x=3, and \; y=2

Region presented by  x+y\geq 8 . The line x+y=8  meets the coordinate axes at A(8,0) and B(0,8)   respectively. By joining these points are obtain the line  x+y=8 . Clearly,(0,0) does not satisfies the

equation x+y\geq 8 . So, the region in xy plane which does not contain the origin represents the solution set of the equation x+y\geq 8.

Region presented by x+4y\geq 12 . The line x+4y=12  meets the coordinate axes at C(12,0 ) and D(0,3) respectively. By joining these points are obtain the line x+4y=12. Clearly, (0,0)  satisfies the

equation x+4y\geq 12 . So, the region in xy plane which does not contain the origin represents the solution set of the equation x+4y\geq 12.

The line x=3 is the line that passes through the point (3,0) and is parallel to y-axis. x\geq 3 is the region to the right the line x=3.

The line y=2  is the line that passes through the point (0,12) and is parallel to x-axis yx\geq 2 is the region above the line y=2.

The value of z at these corner points are as follows

\begin{array}{|c|c|} \hline \text { Corner Points } & z=2 x+4 y \\ \hline E(3,5) & 2 \times 3+4 \times 5=26 \\ \hline F(6,2) & 2 \times 6+4 \times 2=20 \\ \hline \end{array}

Therefore, the maximum value of objective function z is 20 at the point F(6,2)

Hence,  x=6  and y=2  is the optimal solution of the given LPP.

Thus, the optimal of z is 20.

 

 

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