16 g of oxygen has same of molecules as in

(i) 16 g of CO

(ii) 28 g of N_{2}

(iii) 14 g of N_{2}

(iv)) 1.0 g of H_{2}

Answers (1)

The answer are the options (iii) and (iv)

Explanation: 1 mole or the number of molecules of oxygen in 16g Of oxygen is

\frac{16}{32}\times \left ( 6.023 \times 10^{23} \right )

=0.5\times \left ( 6.023\times 10^{23} \right ) molecules

In 14g or N2  and 1 g of H2  contain 0.5 moles. Therefore they will also contain 0.5\times \left ( 6.023\times 10^{23} \right ) molecules

Number of molecules of N2

=\frac{14}{28}\times \left ( 6.023\times 10^{23} \right )

=0.5\times \left ( 6.023\times 10^{23} \right ) molecules

Number of molecules of H2

=\frac{1}{2}\times 6.023\times 10^{23}

=0.5\times \left ( 6.023\times 10^{23} \right ) molecules

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