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Hydrogen gas is prepared in the laboratory by reacting dilute HCI with granulated zinc. Following reaction takes place.

Zn + 2HCl -ZnCl_{2}+ H_{2}

Calculate the volume of hydrogen gas liberated at STP when 32.65 g of zinc reacts With HCI. 1 mol of a gas occupies 22.7 L volume at STP; atomic mass of Zn = 65.3 u.

Answers (1)

Given that 65.3 g of Zn reacts with HCI to form 22.7 of H2(g)

Therefore, 32.65 g of Zn at STP reacts with HCI to form =\frac{22.7\times 32.65}{65.3}=11.35L

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