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The number of atoms present in one mole of an element is equal to Avogadro number. Which of the following element contains the greatest number of atoms?

(i) 4 g of He

(ii) 46g Na

(iii) 0.40 g of Ca

(iv) 12g He

Answers (1)

The answer is the option (iv) 12g He

Explanation:

Using the previous formula,

12 g He=3 moles Of He

Number of atoms of He $=3\times N_{A}$

Number of atoms of He $=3\times\left ( 6.022\times 10^{23} \right )$

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