# Calcium carbonate reacts with aqueous HCl to give and  according to the reaction given below:What mass of  will be formed when 250 mL of 0.76 M HCl reacts with 1000 g of  ? Name the limiting reagent. Calculate the number of moles of  formed in the reaction.

Number of moles of HCI=

Given: Mass of  = 1000 g

Number of moles of =

Referring to the equation, 1 mol of  (s) needs 2 mol of HCI (aq), the ratio is 1:2.

Hence, for 10 mol of  (s), the number of moles of HCI required would be:

But only 0.19 mol of HCI (aq) is available and therefore, HCI is limiting reagent.

Amount of  will depend on the amount of HCl present. 2 mol of HCl (aq), gets 1 mol of , the ratio is 2:1.

Thus, 0.19 mol of HCl will get=

0.095 ×molar mass of  = 0.095 ×111 = 10.54 g

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