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Construct the following and give justification :

A triangle PQR given that QR = 3cm, \angle PQR=45^{\circ} and QP – PR = 2 cm.

Answers (3)

Given : QR = 3cm, \angle PQR=45^{\circ} , QP – PR = 2 cm.

Steps of Construction :

1. Draw line QR = 3 cm

2. Draw line QB with 45^{\circ} angle at Q.

3. Make an arc on QB of 2cm radius intersecting at A

4. Join AR

5. Bisect AR and extend it so it intersects QB at P

6. Join PR

PQR is the required triangle.                         

Justification:

P lies on perpendicular bisector of AB.

Hence, PA = PQ

QA = PQ – PA           

QA = PQ – PR           \left (\because PA = PR \right )

 

Posted by

infoexpert21

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B

Posted by

naveenkumar130301

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PA=PR

Posted by

Suryaprakash

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