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Electronegativity of carbon atoms depends upon their state of hybridisation. In which of the following compounds, the carbon marked with asterisk is most electronegative?

(i) CH_3 - CH_{2}-^{\ast }CH_{2} -CH_{3}
(ii) CH_{}3 - ^{\ast}CH = CH - CH_{3}
(iii) CH_{3} - CH_{2} - C \equiv ^{\ast } CH
(iv) CH_{3} - CH_{2} - CH = ^{\ast}CH_{2}

Answers (1)

The answer is the option (iii) CH_{3} - CH_{2} - C \equiv ^{\ast }CH

Explanation: The electronegativity of the carbon atom depends on its hybridisation state and the percentage of ‘s’ character. It is directly proportional to the ‘s’ character. Here we have sp hybridised carbon having 50 percent s character. 

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