How will you convert benzene into
(i) p – nitrobromobenzene
(ii) m – nitrobromobenzene

Answers (1)

(i) Converting benzene into p-nitro bromobenzene:

C_{6}H_{6} + Br_{2} (In presence of anhyd. FeBr_{3}) → C_{6}H_{5} Br_{2}+HBr

C_{6}H_{5}Br + Conc. HNO_{3} + Conc. H_{2}SO_{4} → p-nitrobromobenzene

(ii) Converting benzene into m-nitrobromobenzene:

C_{6}H_{6} + Conc. HNO_{3} + Conc. H_{2}SO_{4}C_{6}H_{5}NO_{2}

C_{6}H_{5}NO_{2} + Br (In presence of anhyd. FeBr_{3}) → m-nitrobromobenzene

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