If the coefficient of performance of a refrigerator is 5 and operates at the room temperature, find the temperature inside the refrigerator.

Answers (1)

\beta=\frac{T_2}{T_1-T_2}

T_1=27+273=300K

5=\frac{T_{2}}{300-T_{2}}

 On solving, we get

T_2=250K

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