In Figure, common tangents AB and CD to two circles intersect at E. Prove that AB = CD.
To Prove : AB = CD
We know that the length of tangents drawn from some point to a circle is equal.
So, EB = ED
AE = CE
Here AB = AE + EB
CD = CE + ED
From Euclid axiom is equals are added in equals then the result is also equal.
AB = CD
Hence Proved