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In Figure, common tangents AB and CD to two circles intersect at E. Prove that AB = CD.

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To Prove : AB = CD
We know that the length of tangents drawn from some point to a circle is equal.
So,     EB = ED
AE = CE
Here    AB = AE + EB
CD = CE + ED
From Euclid axiom is equals are added in equals then the result is also equal.
\therefore  AB = CD
Hence Proved

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