In Figure, if ∠AOB = 125°, then ∠COD is equal to
(A) 62.5° (B) 45° (C) 35° (D) 55°
Answer (D)
Solution
Given : ∠AOB = 125°
Let ∠COD = x°
As we know the sum of opposite sides angles of a quadrilateral circumscribing a circle is equal to 180°.
Hence
∠AOB + ∠COD = 180°
125° + ∠COD = 180°
x° = 180° – 125° ( ∠COD = x°)
x° = 55°
Hence, ∠COD = 55°