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  • In Figure, if ∠AOB = 125°, then ∠COD is equal to (A) 62.5° (B) 45°(C) 35°(D) 55°

In Figure, if ∠AOB = 125°, then ∠COD is equal to

(A) 62.5°                     (B) 45°                        (C) 35°            (D) 55°

Answers (1)

Answer (D)
Solution
Given : ∠AOB = 125°
Let       ∠COD = x°
As we know that the sum of opposite sides angles of a quadrilateral circumscribing a circle is equal to 180°.
Hence
∠AOB + ∠COD = 180°
125° + ∠COD = 180°
x° = 180° – 125°        (\mathbb{Q}  ∠COD = x°)
x° = 55°
Hence, ∠COD = 55°

 

Posted by

infoexpert27

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