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In the double displacement reaction between aqueous potassium iodide and aqueous lead nitrate, a yellow precipitate of lead iodide is formed. While performing the activity if lead nitrate is not available, which of the following can be used in place of lead nitrate?

(a) Lead sulphate (insoluble)

(b) Lead acetate

(c) Ammonium nitrate

(d) Potassium sulphate

Answers (1)

Ans. (b)

2KI (aq)+Pb(NO_{3})_{2}(aq)\rightarrow PbI_{2}(s)+2KNO_{3}

Potassium Iodide(KI) and lead nitrate Pb(NO_{3})_{2}  dissociate in their aqueous states to form ions.

Precipitates of lead iodide (PbI_2) are formed.

Lead sulphate being insoluble in water does not give Pb^{2+} ions which can combine with I^-  to form (PbI_2)

 

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