Let y varies directly as x. If y = 12 when x = 4, then write a linear equation. What is the value of y when x = 5?
Answer:
y = 3x, y = 15 when x = 5.
Solution:
It is given that y varies directly as x
y = kx (Here k is constant)
For finding k, we can use the given condition y = 12 when x = 4
12 = k(4)
k = 3
Hence the equation is y = 3x
When x = 5 then the value of y is:
y = 3(5)
y = 15
Hence y = 15 when x = 5.