Match the reagent from Column I which on reaction with CH_{3} -CH=CH_{2} gives some product given in Column II as per the codes given below :

Column I

(i) O_{3}/Zn + H_{2}O

(ii)KMnO_{4}/H^{+}

(iii) KMnO_{4}/OH^{-}

(iv) H_{2}O/H^{+}

(v)B_{2}H_{6}/NaOH and H_{2}O_{2}

Column II

(a) Acetic acid and CO_{2}

(b) Propan-1-ol

(c) Propan-2-ol

(d) Acetaldehyde and formaldehyde

(e) Propane-1,2-diol

 

Answers (1)

 (i) → (d); (ii) → (a); (iii) → (e); (iv) → (c); (v) → (b)

Explanation:

(i)O_{3}/Zn + H_{2}O: Two carbonyl compounds are obtained on ozonolysis of alkene

(ii) KMnO_{4}/H^{+}: Propene gives CH_{3}COOH and CO_{2} on reacting with KMnO_{4} in an acidic medium.

                              CH_{3} - CH \equiv CH^{2} + KMnO_{4}/H^{+} \rightarrow CH_{3}COOH + CO_{2}

(iii) KMnO_{4}/OH^{-}-: Alkaline KMnO_{4}is decolourised by propene

(iv) H_{2}O/H^{+}: Propanol-2 is obtained when H_{2}O is added to propene

                                CH_{3}- CH = CH_{2} + H^{+}/^{-}OH \rightarrow CH_{3}-CH(OH)-CH_{3}

(v) B_{2}H_{6}/NaOH and H_{2}O_{2}: Propanol-1 is obtained as a product

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