One mole of oxygen gas at STP is equal to ________

(i) 6.022\times 10^{23} molecules of oxygen

(ii)  6.022\times 10^{23} atoms of oxygen

(iii) 16 g of oxygen

(iv) 32 g of oxygen

Answers (1)

The answer are the options (i) and (iv)

Explanation:

1 mole of oxygen gas at STP = 6.022\times 10^{23} molecules of oxygen (which is the Avogadro number)

1 mole O_{2}=32g \; of \; O_{2}

Thus, one mole of O_{2} is equal to the molecular weight of oxygen and the Avogadro number.

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