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Show that the points A (1, 2), B (– 1, – 16) and C (0, – 7) lie on the graph of the linear equation  y = 9x – 7.

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The given linear equation is y = 9x – 7 and the points are A(1, 2), B(–1, –16) and C(0, –7)

If the points lie on the graph then it must be satisfy the equation y = 9x – 7

Put x = 1,         y = 9 – 7

y = 2

Put x = –1        y = –9 – 7

                        y = –16

Put x = 0          y = 0 – 7

                        y = -7

Here all the points satisfy the equation y = 9x – 7.

Therefore all the points lie on the graph of the linear equation y = 9x – 7

Hence proved

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