The addition of HBr to 1-butene gives a mixture of products A, B and C

 CH_{3}-CH_{2}-CH_{2}-CH_{2}-Br

                                                                                                        (C)

The mixture consists of
(i) A and B as major and C as minor products
(ii) B as major, A and C as minor products
(iii) B as minor, A and C as major products
(iv) A and B as minor and C as major products

Answers (1)

The answer is the option (i) A and B as major and C as minor products.

Explanation: According to Markovnikov’s rule, the major product is 2-Bromobutane, and the minor product is I-Bromobutane. Butane-1 is unsymmetrical. 2-Bromobutane has chiral carbon and hence exists in two enantiomers.

Thus, it is clear that the major products are A & B while the minor product is C.

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